-x^2+2x=0.6

Solution for -x^2+2x=0.6 equation:

-x^2+2x=0.6

We move all terms to the left:

-x^2+2x-(0.6)=0

We add all the numbers together, and all the variables

-1x^2+2x-0.6=0

a = -1; b = 2; c = -0.6;
Δ = b2-4ac
Δ = 22-4·(-1)·(-0.6)
Δ = 1.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{1.6}}{2*-1}=\frac{-2-\sqrt{1.6}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{1.6}}{2*-1}=\frac{-2+\sqrt{1.6}}{-2}
$